A particular piece of music was played by 91 pianists and for each pianist, the number of incorrect notes was recorded. The results are summarised in the table. [Table: Number of incorrect notes | Frequency] [Table: 1–5 | 10] [Table: 6–10 | 5] [Table: 11–20 | 26] [Table: 21–40 | 32] [Table: 41–70 | 18]
- (a)Draw a histogram to represent this information.[5]
- (b)State which class interval contains the lower quartile and which class interval contains the upper quartile. Hence find the greatest possible value of the interquartile range.[2]
- (c)Calculate an estimate for the mean number of incorrect notes.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [M1] At least 3 class widths correct and used in a calculation
- [M1] At least 3 correct frequency densities unsimplified – FT their class widths
- [A1] All correct heights on a histogram using a linear vertical scale from zero – no FT
- [B1] Correct upper bar ends (5.5, 10.5, 20.5, 40.5, 70.5) and 4 correct lower bar ends of 5.5, 10.5, 20.5, 40.5. Condone 0 or 1.
- [B1] Linear scales with at least 3 values indicated on each axis, vertical scale from 0, axes labelled 'fd' and 'no. of (incorrect) notes', or better.
- [B1] Both UQ and LQ correct
- [B1 FT] Subtract lower end of their LQ interval from upper end of their UQ interval
- [M1] At least 4 midpoints correct and used
- [M1] Correct formula with their midpoints (not upper boundary, lower boundary, class width, frequency density, frequency or cumulative frequency)
- [A1] Accept 26 or 27
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