Three coins A, B and C are each thrown once. • Coins A and B are each biased so that the probability of obtaining a head is 2/3. • Coin C is biased so that the probability of obtaining a head is 2/5. The random variable X is the number of heads obtained when the three coins are thrown.
- (a)Show that the probability of obtaining exactly 2 heads and 1 tail is 4/9.[3]
- (b)Draw up the probability distribution table for X.[3]
- (c)Given that E(X) = 32/15, find Var(X).[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [M1] One 3 factor probability with 3, 3, 5 as denominators
- [M1] 3 factor probabilities for 2 or 3 correct scenarios added, no incorrect scenarios
- [A1] AG, Total of 3 products with clear context
- [B1] Probability distribution table with correct outcomes with at least one probability, allow extra outcome values if probability of zero stated'
- [B1] 2 of P(0), P(1) and P(3) correct
- [B1 FT] 3 or 4 probabilities sum to 1 with P(2) correct
- [M1] Substitute their attempts at scores in correct variance formula, must have '- mean²' (FT if calculated) (condone probs not summing to 1); must be at least 2 non-zero values
- [A1] Accept 26 or 27
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