In a certain country, the weather each day is classified as fine or rainy. The probability that a fine day is followed by a fine day is 0.75 and the probability that a rainy day is followed by a fine day is 0.4. The probability that it is fine on 1 April is 0.8. The tree diagram below shows the possibilities for the weather on 1 April and 2 April. [Figure X.X]
- (a)Complete the tree diagram to show the probabilities. [Figure X.X][1]
- (b)Find the probability that 2 April is fine.[2]
- (c)Let X be the event that 1 April is fine and Y be the event that 3 April is rainy. Find the value of P(X ∩ Y).[3]
- (d)Find the probability that 1 April is fine given that 3 April is rainy.[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B1] All probabilities correct, may be on branch or next to 'Fine/Rainy' Ignore additional branches.
- [M1] Correct or FT from their diagram unsimplified, all probabilities 0<p<1. Partial evaluation only sufficient when correct. Accept working in 4(b) or by the tree diagram.
- [A1] From supporting working
- [M1] a×b×c + a × 1-b × d, 0 < c, d ≤ 1, a, b consistent with their tree diagram or correct, no additional terms
- [A1] At least one term correct, accept unsimplified
- [A1] Final answer
- [B1 FT] their (c) + e × f × g + e × (1-f) × h, 0 < g, h < 1, e, f consistent with their tree diagram, or correct
- [M1] their 4(c) (or correct)/their previously calculated and identified P(Y) or a denominator involving 3 or 4 3-factor probability terms consistent with their tree diagram & third factor 0 <p<1
- [A1] (0.7458...)
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