A bag contains 5 red balls and 3 blue balls. Sadie takes 3 balls at random from the bag, without replacement. The random variable X represents the number of red balls that she takes.
- (a)Show that the probability that Sadie takes exactly 1 red ball is 15/56.[2]
- (b)Draw up the probability distribution table for X.[3]
- (c)Given that E(X) = 15/8, find Var(X).[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [M1] (5C1 × 3C2) / 8C3 or (5/8) × (3/7) × (2/6) × 3
- [A1] AG, WWW
- [B1] Probability distribution table with correct outcomes with at least one probability less than 1, allow extra outcome values if probability of zero stated.
- [B1] 2 of P(0), P(2) and P(3) correct
- [B1 FT] 4th probability correct or FT sum of 3 or more probabilities = 1, with P(1) correct
- [M1] Substitute their attempts at scores in correct variance formula, must have ' - mean²' (FT if mean calculated) (condone probabilities not summing to 1 for this mark)
- [A1]
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →