A car of mass 1800 kg is travelling along a straight horizontal road. The power of the car's engine is constant. There is a constant resistance to motion of 650 N.
- (a)Find the power of the car's engine, given that the car's acceleration is 0.5 m s⁻² when its speed is 20 m s⁻¹.[3]
- (b)Find the steady speed which the car can maintain with the engine working at this power.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [3] (a) DF - 650 = 1800×0.5 [DF = 1550]
- [3] (a) Apply Newton's second law, 3 terms
- [3] (a) P/20 - 650 = 1800×0.5
- [3] (a) [Power P = 1550 × 20 =] 31 000 W or 31 kW
- [2] (b) 31000/v - 650 = 0
- [2] (b) Use P = Fv with F = 650
- [2] (b) v = 47.7 ms⁻¹
- [2] (b) FT on their P≠ 13 000 Allow 620/13
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →