Two particles of masses 0.8 kg and 0.2 kg are connected by a light inextensible string that passes over a fixed smooth pulley. The system is released from rest with both particles 0.5 m above a horizontal floor (see diagram). In the subsequent motion the 0.2 kg particle does not reach the pulley. [Figure 5.1]
- (a)Show that the magnitude of the acceleration of the particles is 6 m s⁻² and find the tension in the string.[4]
- (b)When the 0.8 kg particle reaches the floor it comes to rest. Find the greatest height of the 0.2 kg particle above the floor.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [M1] Apply Newton's 2nd law to either particle or to the system
- [A1] Any 2 correct equations
- [M1] Attempt to solve for either a or T
- [A1] AG. Both correct
- [M1] Attempt to find v or v² as 0.8 kg particle reaches the ground using a from 5(a)
- [M1] Attempt to find the extra height reached by 0.2 kg particle using v² from previous M1 mark
- [A1] Greatest height = 0.5 + 0.5 + 0.3 = 1.3 m
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