The coordinates (x, y) of a general point of a curve satisfy the differential equation x dy/dx = (1 - 2x²)y, for x > 0. It is given that y = 1 when x = 1. Solve the differential equation, obtaining an expression for y in terms of x.
- The coordinates (x, y) of a general point of a curve satisfy the differential equation x dy/dx = (1 - 2x²)y, for x > 0. It is given that y = 1 when x = 1. Solve the differential equation, obtaining an expression for y in terms of x.[6]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- Separate variables correctly and attempt integration of at least one side
- Obtain term In y
- Obtain terms Inx - x²
- Use x = 1, y = 1 to evaluate a constant, or as limits, in a solution containing at least 2 terms of the form alny, blnx and cx²
- Obtain correct solution in any form
- Rearrange and obtain y = xe^(1-x²)
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