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A-LevelMathematicsProbability and statistics9709/61 · Oct/Nov 2019 · Q69 Marks

The word STEEPLECHASE has 12 letters.

  1. (i)Find the number of different ways in which all 12 letters of the word STEEPLECHASE can be arranged so that all four Es are together.[1]
  2. (ii)Find the number of different ways in which all 12 letters of the word STEEPLECHASE can be arranged so that the Ss are not next to each other.[4]
  3. (iii)Four letters are selected from the 12 letters of the word STEEPLECHASE. Find the number of different selections if the four letters include exactly one S.[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [B1] Exact value
  2. [B1] Total no of ways = 12!/(2!4!) = 9979200 (A)
  3. [B1] With Ss together = 11!/4! = 1663200 (B)
  4. [M1] Correct or (12!/m) - (8!/n), m,n integers > 1 or their identified total – their identified Ss together
  5. [A1] Exact value
  6. [M1] Cx seen alone or times K>1
  7. [B1] C3 or C2 or 'C1 alone
  8. [M1] No extras
  9. [A1]

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About this question

Topic
Probability and statistics, A-Level Mathematics (syllabus 9709). Structured question, 9 marks.
Source
A-Level Mathematics, Oct/Nov 2019 Paper 6 Variant 1, question 6.

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