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A-LevelMathematicsDifferential equations9709/32 · Oct/Nov 2019 · Q68 Marks

The variables x and θ satisfy the differential equation sin(θ/2) dx/dθ = (x + 2) cos(θ/2) for 0 < θ < π. It is given that x = 1 when θ = π/3. Solve the differential equation and obtain an expression for x in terms of cos θ.

  1. (a)The variables x and θ satisfy the differential equation sin(θ/2) dx/dθ = (x + 2) cos(θ/2) for 0 < θ < π. It is given that x = 1 when θ = π/3. Solve the differential equation and obtain an expression for x in terms of cos θ.[8]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [B1] Separate variables correctly to obtain ∫1/(x+2) dx = ∫cot(θ/2) dθ or equivalent integrands. Integral signs SOI
  2. [B1] Obtain term ln(x+2)
  3. [M1] Obtain term of the form klnsin(θ/2)
  4. [A1] Obtain term 2lnsin(θ/2)
  5. [M1] Use x = 1, θ = π/3 to evaluate a constant, or as limits, in an expression containing pln(x + 2) and qln(sin(θ/2))
  6. [A1] Obtain correct solution in any form e.g. ln(x+2) = 2lnsin(θ/2) + ln12
  7. [M1] Remove logarithms and use correct double angle formula
  8. [A1] Obtain answer x=4-6cosθ

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About this question

Topic
Differential equations, A-Level Mathematics (syllabus 9709). Structured question, 8 marks.
Source
A-Level Mathematics, Oct/Nov 2019 Paper 3 Variant 2, question 6.

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