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A-LevelMathematicsTrigonometry9709/22 · Oct/Nov 2019 · Q810 Marks

Express 0.5 cos θ – 1.2 sin θ in the form R cos(θ + α), where R > 0 and 0° < α < 90°, giving the value of α correct to 2 decimal places.

  1. (i)Express 0.5 cos θ – 1.2 sin θ in the form R cos(θ + α), where R > 0 and 0° < α < 90°, giving the value of α correct to 2 decimal places.[3]
  2. (ii)Hence solve the equation 0.5 cos θ – 1.2 sin θ = 0.8 for 0° < θ < 360°.[4]
  3. (iii)Determine the greatest and least possible values of (3 – cos θ + 2.4 sin θ)² as θ varies.[3]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [B1] State R = 1.3 or 10/3 (Not √1.69)
  2. [M1] Use appropriate trigonometry to find α (AWRT ±1.18rads, AWRT ±0.391rads, AWRT ±67.4°, AWRT ±22.6°)
  3. [A1] Obtain 67.38 with no errors seen (AWRT)
  4. [M1] Carry out correct method to find one value of θ between 0 and 360
  5. [A1] Obtain 240.6 (or 344.6)
  6. [M1] Carry out correct method to find second value of θ between 0 and 360 (Must be using either degrees throughout or radians throughout for M marks)
  7. [A1] Obtain 344.6 (or 240.6)
  8. [M1] Recognise expression as [3 – 2Rcos(θ + α)]²
  9. [A1] Obtain [3 – 2 * (-1.3)]² and hence 31.36 or 31.4
  10. [A1] Obtain [3 – 2 * 1.3]² and hence 0.16

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 10 marks.
Source
A-Level Mathematics, Oct/Nov 2019 Paper 2 Variant 2, question 8.

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