Lengths of a certain species of lizard are known to be normally distributed with standard deviation 3.2 cm. A naturalist measures the lengths of a random sample of 100 lizards of this species and obtains an α% confidence interval for the population mean. He finds that the total width of this interval is 1.25 cm.
- Find α.[5]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.
- [M1] 2z * (3.2 / sqrt(100)) = 1.25; OE Allow without '2 x'
- [A1] z = 1.953; SOI
- [M1] Φ(‘their 1.953’) (= 0.9746)
- [M1] = 1 - 2(1 – 0.9746’); OE
- [A1] α = 94.9 or 95; CWO
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