The diagram shows the curve with equation y = √(1 + 3cos²(x/2)) for 0 ≤ x ≤ π. The region R is bounded by the curve, the axes and the line x = π. [Figure X.X]
- (i)Use the trapezium rule with two intervals to find an approximation to the area of R, giving your answer correct to 3 significant figures.[3]
- (ii)The region R is rotated completely about the x-axis. Without using a calculator, find the exact volume of the solid produced.[5]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [B1] Use y values 2, √2.5, 1 or equivalents
- [M1] Use correct formula, or equivalent, with h = ½π and three y values
- [A1] Obtain ½π(2 + 2√2.5 + 1) or equivalent and hence 4.84
- [B1] State or imply volume is ∫₀^π π(1 + 3cos²(x/2)) dx
- [M1] Use appropriate identity to express integrand in form k₁ + k₂ cos x
- [A1] Obtain ∫π(5/2 + 3/2 cos(x)) dx or ∫(π(5/2 + 3/2 cos(x))) dx
- [A1] Integrate to obtain π(⁵/₂x + ³/₂sin(x)) or ⁵/₂πx + ³/₂πsin(x)
- [A1] Obtain ⁵/₂π² with no errors seen
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →