A curve has parametric equations x = t + ln(t + 1), y = 3te²ᵗ.
- (i)Find the equation of the tangent to the curve at the origin.[5]
- (ii)Find the coordinates of the stationary point, giving each coordinate correct to 2 decimal places.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [M1] Use product rule to differentiate y obtaining k₁e²ᵗ + k₂te²ᵗ
- [A1] Obtain correct 3e²ᵗ + 6te²ᵗ
- [B1] State derivative of x is 1 + 1/(t+1)
- [M1] Use dy/dx = (dy/dt) / (dx/dt) with t = 0 to find gradient
- [A1] Obtain y = ½x or equivalent
- [M1] Equate dy/dx or dy/dt to zero and solve for t Allow full marks if correct solution is obtained but dx/dt is incorrect
- [A1] Obtain t = –½
- [A1] Obtain x = -1.19
- [A1] Obtain y = -0.55
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