A box contains 6 identical-sized discs, of which 4 are blue and 2 are red. Discs are taken at random from the box in turn and not replaced. Let X be the number of discs taken, up to and including the first blue one.
- (i)Show that P(X = 3) = 1/15[2]
- (ii)Draw up the probability distribution table for X.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- EITHER: (M1 probabilities in order 2/6 x 1/5 x 4/4, p, q, r ≤ 6 and p≥ q ≥ r, r ≥4, accept × 1 as 4/r
- A1) Needs either P(RRB) OE stated or identified on tree diagram.
- OR1: (M1 probabilities stated clearly, 2C2/6C2 x 4C1/4C1 or x 1 or x 4/4 included
- A1) Needs either P(RRB) OE stated or identified on tree diagram.
- OR2: (M1 probabilities in order 2C1/6C1 x 1C1/5C1 x 4C1/4C1, p. q. r ≤6 and p≥q≥r, r≥4 (x 4C1/4C1 or x 1 or x 4/4 acceptable)
- A1) Needs either P(RRB) OE stated or identified on tree diagram.
- B1 Probability distribution table drawn with at least 2 correct x values and at least 1 probability. All probabilities 0 <p<1.
- B1 P(1) or P(2) correct unsimplified, or better, and identified.
- B1 All probabilities in table, evaluated correctly OE. Additional x values must have a stated probability of 0
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