The equation of a curve is 2x⁴ + xy³ + y⁴ = 10.
- (i)Show that dy/dx = - (8x³ + y³) / (3xy² + 4y³)[4]
- (ii)Hence show that there are two points on the curve at which the tangent is parallel to the x-axis and find the coordinates of these points.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [B1] (i) State or imply y³ + 3xy² dy/dx as derivative of xy³
- [B1] (i) State or imply 4y³ dy/dx as derivative of y⁴
- [M1] (i) Equate derivative of the LHS to zero and solve for dy/dx
- [A1] (i) Obtain the given answer
- [*M1] (ii) Equate numerator to zero
- [A1] (ii) Obtain y = -2x, or equivalent
- [DM1] (ii) Obtain an equation in x or y
- [A1] (ii) Obtain final answer x = −1, y = 2 and x = 1, y = −2
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