The equation x³ = 3x + 7 has one real root, denoted by α.
- (i)Show by calculation that α lies between 2 and 3.[2]
- (ii)Two iterative formulae, A and B, derived from this equation are as follows: xn+1 = (3xn + 7)³, (A) xn+1 = xn² - 7 / 3, (B) Each formula is used with initial value x₁ = 2.5. Show that one of these formulae produces a sequence which fails to converge, and use the other formula to calculate α correct to 2 decimal places. Give the result of each iteration to 4 decimal places.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [M1] (i) Calculate value of a relevant expression or expressions at x = 2 and x = 3
- [A1] (i) Complete the argument correctly with correct calculated values
- [M1] (ii) Use an iterative formula correctly at least once
- [A1] (ii) Show that (B) fails to converge
- [A1] (ii) Using (A), obtain final answer 2.43
- [A1] (ii) Show sufficient iterations to justify 2.43 to 2 d.p., or show there is a sign change in (2.425, 2.435)
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