The function f : x → 6 − 4 cos(½x) is defined for 0 ≤ x ≤ 2π.
- (i)Find the exact value of x for which f(x) = 4.[3]
- (ii)State the range of f.[2]
- (iii)Sketch the graph of y = f(x).[2]
- (iv)Find an expression for f⁻¹(x).[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2014). The mark or mark type is shown in brackets.
- [1] Set f(x) = 4: 6 − 4cos(½x) = 4 → 4cos(½x) = 2. Makes cos(½x) the subject.
- [1] cos(½x) = ½. Looks up “½x” before ×2
- [1] ½x = π/3 → x = 2π/3. co (120° gets A0 – decimals A0)
- [2] The range of f is 2 ≤ f(x) ≤ 10. condone <
- [1] The sketch graph should show a point of inflexion at x = π.
- [1] The sketch graph should be fully correct.
- [1] Let y = 6 − 4cos(½x). Rearrange to make cos(½x) the subject: cos(½x) = (6-y)/4. Makes cos⁻¹(½x) the subject
- [1] Rearrange further: ½x = cos⁻¹((6-y)/4). Order of operations correct (M marks allowed if + for –)
- [1] x = 2cos⁻¹((6-y)/4). Replace y with x for inverse function: f⁻¹(x) = 2cos⁻¹((6-x)/4). oe - needs to be a function of x not y
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