Prove the identity cot²θ - tan²θ ≡ 4 cot 2θ cosec 2θ.
- (a)Prove the identity cot²θ - tan²θ ≡ 4 cot 2θ cosec 2θ.[4]
- (b)Hence solve the equation cot²x - tan²x = 5 sec 2x for 0° < x < 90°.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [M1] Express the left hand side in terms of sine and cos. cos²θ/sin²θ - sin²θ/cos²θ
- [M1] Combine to a single term and factorise the numerator. (cos²θ - sin²θ)(cos²θ + sin²θ)/(sin²θcos²θ)
- [M1] Use correct double angle formulae in numerator and denominator. 4cos2θ/(sin²2θ)
- [A1] Obtain 4 cot 2θ cosec 2θ from correct working. 4cos2θ/(sin2θsin2θ)
- [M1*] Use the identity to obtain an expression in one trigonometric function. cot²2x = 5/4 or tan²2x = 4/5
- [A1] Obtain tan² 2x = 4/5. OE
- [DM1] Obtain one solution e.g. 20.9°. AWRT
- [A1] Obtain a second value e.g. 69.1° and no extras in range. AWRT
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