A random variable X has the distribution N(10, 12). Two independent values of X, denoted by X₁ and X₂, are chosen at random.
- (a)Write down the value of P(X₁ > X₂).[1]
- (b)Find P(X₁ > 2X₂ −3).[5]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [B1] 0.5
- [B1] E(X₁ - 2X₂ + 3) = 10 - 20 + 3 [= -7] or E(2X₂ - X₁ - 3) = 20 - 10 - 3 [= 7] Or equivalent using X₁ – 2X₂ = 10 – 20 [= −10] or 2X₂ - X₁ = 20 – 10 [= +10].
- [B1] Var(X₁ - 2X₂ + 3) = 12 + 2² × 12 + 0 [= 60]
- [M1] 0-(-7) / √'60' [= 0.904] Or numerator 3- '10' or -3-('-10'), but not '-3 -10' (i.e. numerator must be '7' or '-7').
- [M1] 1 – Φ('0.904') For area consistent with their working.
- [A1] = 0.183
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