The time taken in minutes for a certain daily train journey has a normal distribution with standard deviation 5.8. For a random sample of 20 days the journey times were noted and the mean journey time was found to be 81.5 minutes.
- (a)Calculate a 98% confidence interval for the population mean journey time.[3]
- (b)A student was asked for the meaning of this confidence interval. The student replied as follows. 'The times for 98% of these journeys are likely to be within the confidence interval.' Explain briefly whether this statement is true or not.[1]
- (c)Two independent 98% confidence intervals are found. Given that at least one of these intervals contains the population mean, find the probability that both intervals contain the population mean.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [M1] 81.5 ± z x 5.8/√20
- [B1] z = 2.326
- [A1] 78.5 to 84.5 (3sf)
- [B1] Not true. C. I. is for mean time, not individual times. Both comments needed.
- [M1] 0.98^2 / (1-0.02^2)
- [A1] = 0.961 (3sf)
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