Salah decides to attempt the crossword puzzle in his newspaper each day. The probability that he will complete the puzzle on any given day is 0.65, independent of other days.
- (a)Find the probability that Salah completes the puzzle for the first time on the 5th day.[1]
- (b)Find the probability that Salah completes the puzzle for the second time on the 5th day.[2]
- (c)Find the probability that Salah completes the puzzle fewer than 5 times in a week (7 days).[3]
- (d)Use a suitable approximation to find the probability that Salah completes the puzzle more than 50 times in a period of 84 days.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [B1] AWRT
- [M1] (0.35)³ ×(0.65)² × k, where k is an integer. 1 ≤ k ≤ 5 no + or -
- [A1]
- [M1] One term 7Cx(p)x(1-p)7-x, 0<p<1, 0<x<7.
- [A1] Correct expression, accept unsimplified, no terms omitted leading to final answer
- [B1] AWRT
- (M1) One term 7Cx(p)x(1-p)7-x, 0<p<1, 0<x<7.
- (A1) Correct expression, accept unsimplified, no terms omitted leading to final answer.
- (B1) AWRT
- [B1] 54.6 and 19.11 seen, allow unsimplified. May be seen in the standardisation formula ([σ = ] 4.371 or (7√39)/10 implies correct variance). Incorrect notation is penalised, but condone use of values in standardisation formula.
- [M1] Substituting their μ and their positive σ into the ±standardising formula (any number), not their σ², or √their σ.
- [M1] Use continuity correction 49.5 or 50.5 in their standardisation formula. Note: ±4.1/√19.11 or ±4.1/4.371 seen gains M2 BOD.
- [M1] Appropriate area Φ, from final process, must be a probability.
- [A1] 0.8255 < p ≤ 0.826
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