The heights, in cm, of 200 adults in Barimba are summarised in the following table. Height (h cm) 130 ≤ h < 150 150 ≤ h < 160 160 ≤ h < 170 170 ≤ h < 175 175 ≤ h < 195 Frequency 16 32 76 64 12
- (a)Draw a histogram to represent this information.[4]
- (b)The interquartile range is R cm. Show that R is not greater than 15.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [M1] At least four frequency densities calculated e.g. f/cw (16/20) or (32/10) or (76/10) or (64/5) or (12/20). Condone f/cw ±0.5 if unsimplified. Accept unsimplified, may be read from graph using their scale no lower than 1 cm = fd 2.
- [A1] All bar heights correct on graph, not FT. Using their suitable linear scale with at least three values indicated, no lower than 1 cm = fd 2.
- [B1] Bar ends at 150, 160, 170, 175, 195. Five bars drawn with a horizontal linear scale no lower than 1 cm = 10 cm, with at least three values indicated, 130 < horizontal scale < 195.
- [B1] Axes labelled frequency density (fd) height (h) and cm, OE, or an appropriate title. (Axes may be reversed)
- [M1] 170<h<175 – 160<h<170 UQ and LQ classes seen.
- [A1] 175 – 160 = 15 (If M0 scored, SC B1 for 175 – 160 = 15.)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →