Prove that 2 sin θ cosec 2θ ≡ sec θ.
- (a)Prove that 2 sin θ cosec 2θ ≡ sec θ.[2]
- (b)Solve the equation tan²θ+7 sin θ cosec 2θ = 8 for -π < θ < π.[5]
- (c)Find ∫ 8 sin²(½x) cosec²x dx.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [M1] Express left-hand side in terms of sin θ and cos θ using cosec 2θ = 1/sin 2θ
- [A1] Obtain 1/cos θ and confirm sec θ Answer given – necessary detail needed.
- [*M1] Attempt to obtain quadratic equation in sec θ or cos θ only
- [A1] Obtain sec²θ-1 + (7/2)sec θ = 8 involving one trigonometric ratio Or equivalent, may be unsimplified, but reduce to 2sec²θ+7secθ-18=0 or 18cos²θ-7cosθ-2=0.
- [DM1] Attempt to solve 3-term quadratic equation for sec θ, using a correct method, to find at least one value of θ
- [A1] Obtain any two of the four correct solutions ±0.952, ±1.76 Or greater accuracy.
- [A1] Obtain remaining two correct solutions Or greater accuracy; and no others between –π and π.
- [B1] Identify integrand as 2sec²(½x)
- [M1] Integrate ksec²(½x) to obtain 2k tan(½x)
- [A1] Obtain correct 4 tan(½x) Condone omission of ... + c.
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