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A-LevelMathematicsDifferentiation9709/22 · May/June 2024 · Q47 Marks

A curve is defined by the parametric equations x = 4 cos²t, y = √3 sin 2t, for values of t such that 0 < t < π/2. Find the equation of the normal to the curve at the point for which t = π/6. Give your answer in the form ax+by+c = 0 where a, b and c are integers.

  1. 4A curve is defined by the parametric equations x = 4 cos²t, y = √3 sin 2t, for values of t such that 0 < t < π/2. Find the equation of the normal to the curve at the point for which t = π/6. Give your answer in the form ax+by+c = 0 where a, b and c are integers.[7]

Mark scheme

Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.

  1. [*M1] Obtain forms dx/dt = k₁cos t sin t or dy/dt = k₂cos 2t
  2. [A1] Obtain correct -8cos t sin t or –4sin 2t and 2√3 cos 2t
  3. [*DM1] Attempt value of dy/dx when t = π/6 Need to see attempt at substitution.
  4. [A1] Obtain dy/dx = 1/2
  5. [**M1FT] State or imply gradient of normal is 2 Following their value of the first derivative.
  6. [**DM1] Attempt equation of normal Not tangent and with attempt to find coordinates (3, 3/2).
  7. [A1] Obtain 4x-2y-9 = 0 Or equivalent of requested form.

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About this question

Topic
Differentiation, A-Level Mathematics (syllabus 9709). Structured question, 7 marks.
Source
A-Level Mathematics, May/June 2024 Paper 2 Variant 2, question 4.

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