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A-LevelMathematicsCoordinate geometry9709/12 · May/June 2024 · Q78 Marks

The equation of a circle is (x−6)² + (y+a)² = 18. The line with equation y = 2a−x is a tangent to the circle.

  1. (a)Find the two possible values of the constant a.[5]
  2. (b)For the greater value of a, find the equation of the diameter which is perpendicular to the given tangent.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.

  1. [M1*] (x-6)² + (2a-x+a)² = 18 Replacing y with 2a – x in the circle equation, condone incorrect expansion before substitution.
  2. [A1] 2x² -12x−6ax+9a² +36-18[=0] All terms collected on one side of the equation. May be implied by the discriminant.
  3. [DM1] (12+6a)²-4×2×(9a² +18) [= 0] Correct use of "b² - 4ac" from their 3 term quadratic equation in x, with an x term of the form (m+na)x with both m and n ≠ 0.
  4. [A1] -36a² +144a[+0=0]
  5. [A1] a = 0, a = 4
  6. [B1] [Centre is] (6, -4) or [Point of intersection is] (9, -1)
  7. [B1] [Gradient of diameter] = 1
  8. [B1FT] y+4=x-6 or y+1=x-9 [leading to y = x -10] FT on their point of intersection or their centre with an x co-ordinate of ±6 and gradient = 1.

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About this question

Topic
Coordinate geometry, A-Level Mathematics (syllabus 9709). Structured question, 8 marks.
Source
A-Level Mathematics, May/June 2024 Paper 1 Variant 2, question 7.

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