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A-LevelMathematicsTrigonometry9709/22 · May/June 2023 · Q610 Marks

Show that 4 sin(θ + ¼π) cos(θ – ¼π) = √3 + 2 sin 2θ.

  1. (a)Show that 4 sin(θ + ¼π) cos(θ – ¼π) = √3 + 2 sin 2θ.[4]
  2. (b)Find the exact value of 4 sin(17π/24) cos(17π/24).[2]
  3. (c)Find the exact value of ∫[from 0 to π/8] 4 sin(2x + ¼π) cos(2x – ¼π) dx.[4]

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. 6(a)
  2. [B1] Obtain at least either (½sinθ + ½√3cosθ) or (½cosθ + ½√3sinθ)
  3. [M1] Expand and simplify with correct use of sin² θ + cos² θ =1
  4. [M1] Use sinθcosθ = ½sin2θ
  5. [A1] Confirm given result √3+2sin2θ AG necessary detail required.
  6. 6(b)
  7. [*B1] Identify value of θ is π/6
  8. [DB1] Obtain √3+2sin(π/6) and conclude √3+√2
  9. 6(c)
  10. [B1] Identify integrand as √3 +2 sin4x
  11. [M1] Integrate to obtain form k₁x + k₂ cos 4x
  12. [A1] Obtain correct √3x-½cos4x
  13. [A1] Obtain π√3/8 + ½

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About this question

Topic
Trigonometry, A-Level Mathematics (syllabus 9709). Structured question, 10 marks.
Source
A-Level Mathematics, May/June 2023 Paper 2 Variant 2, question 6.

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