Show that 4 sin(θ + ¼π) cos(θ – ¼π) = √3 + 2 sin 2θ.
- (a)Show that 4 sin(θ + ¼π) cos(θ – ¼π) = √3 + 2 sin 2θ.[4]
- (b)Find the exact value of 4 sin(17π/24) cos(17π/24).[2]
- (c)Find the exact value of ∫[from 0 to π/8] 4 sin(2x + ¼π) cos(2x – ¼π) dx.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- 6(a)
- [B1] Obtain at least either (½sinθ + ½√3cosθ) or (½cosθ + ½√3sinθ)
- [M1] Expand and simplify with correct use of sin² θ + cos² θ =1
- [M1] Use sinθcosθ = ½sin2θ
- [A1] Confirm given result √3+2sin2θ AG necessary detail required.
- 6(b)
- [*B1] Identify value of θ is π/6
- [DB1] Obtain √3+2sin(π/6) and conclude √3+√2
- 6(c)
- [B1] Identify integrand as √3 +2 sin4x
- [M1] Integrate to obtain form k₁x + k₂ cos 4x
- [A1] Obtain correct √3x-½cos4x
- [A1] Obtain π√3/8 + ½
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →