The diagram shows a sector OAB of a circle with centre O. Angle AOB = θ radians and OP = AP = x. [Figure 6.1]
- (a)Show that the arc length AB is 2xθ cos θ.[2]
- (b)Find the area of the shaded region APB in terms of x and θ.[4]
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Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [*B1] OA = 2xcosθ (derived from AP² = (Rcosθ - x)² + (Rsinθ)² = x²) Correct expression containing OA, OA or OA² (allow p, a or r for OA) containing only terms with x and θ but not just OA = 2xcosθ. Do not condone sin π - 2θ until missing brackets recovered or cos(180-2θ) until it becomes -cos2θ etc.
- [DB1] OA = 2xcosθ leading to Arc length = 2xθcosθ AG Complete correct method showing all necessary working. Condone 2xcosθ×θ.
- [M1] Sector area = 1/2 (2xcosθ)² θ OE Using sector formula with a correct OA. Condone cosθ² for cos²θ and missing brackets.
- [M1] Triangle area = 1/2 × 2xcosθ × x sinθ OR 1/2 x² sin(π-2θ) Using a correct triangle formula for the correct triangle. Condone missing brackets and 180 for π.
- [M1] [Area APB =] Their sector area – their triangle area Both expressions must be areas involving terms with x² and θ only. Condone missing brackets and 180 for π for the triangle. Condone calling the sector a segment.
- [A1] [Area APB =] 1/2(2xcosθ)² θ - 1/2 x² sin(π-2θ) [= x²(2θcos²θ - sin2θ)] OE A correct expression. Mark the first unsimplified result of subtraction and ISW any incorrect 'simplifications'.
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