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A-LevelMathematicsProbability and statistics9709/52 · May/June 2022 · Q610 Marks

The 9 letters in the word CROCODILE are: C (2), R (1), O (2), D (1), I (1), L (1), E (1).

  1. (a)Find the number of different arrangements of the 9 letters in the word CROCODILE.[1]
  2. (b)Find the number of different arrangements of the 9 letters in the word CROCODILE in which there is a C at each end and the two Os are not together.[3]
  3. (c)Four letters are selected from the 9 letters in the word CROCODILE. Find the number of selections in which the number of Cs is not the same as the number of Os.[3]
  4. (d)Find the number of ways in which the 9 letters in the word CROCODILE can be divided into three groups, each containing three letters, if the two Cs must be in different groups.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.

  1. B1 [9!/(2!2!) =] 90 720
  2. M1 w!/2! - y, w = 6, 7 y an integer. Condone 2 x w!/2! - y.
  3. M1 a - 6! or a – 720, a an integer resulting in a positive answer.
  4. A1 [1800]
  5. M1 5! x b, b integer >1.
  6. M1 cx (6x5)/2! or 6C2 or 15), c integer > 1.
  7. A1 [1800]
  8. B1 Correct outcome/value for 1 identified scenario. Accept unsimplified. WWW [CCO = 5C1 = 5] [CC_ = 5C2 = 10] [OOC = 5C1 = 5] [OO_ = 5C2 = 10] [C_ _ = 5C3 = 10] [O_ _ = 5C3 = 10]
  9. M1 Add 5 or 6 values of appropriate scenarios only, no additional incorrect scenarios, no repeated scenarios. Accept unsimplified. Condone use of permutations.
  10. A1 [Total =] 50
  11. B1 A correct scenario calculated accurately. Accept unsimplified. [Both Os in group with a C: 5C2 = 10] [Both Os in group without a C: 5C2 × 3C2 = 30] [One O in a C group, one not: 5C1 × 4C2 = 30] [One O with each C: (5C1 × 4C1) ÷2! = 10]
  12. M1 Add 3 or 4 correct scenario values, no incorrect scenarios, accept repeated scenarios. Accept unsimplified.
  13. A1 [Total =] 80
  14. B1 A correct scenario calculated accurately. Accept unsimplified. [CCO O^^ ^^^ = 5C2 = 10] [CC^ O^^ O^^ = 5C1 ×4C2 = 30] [CC^ OO^ ^^^ = 5C1 × 4C1 = 20]
  15. M1 Total subtract 2 or 3 correct scenario values, no incorrect scenarios. Accept unsimplified.
  16. A1 [Total =] 80

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About this question

Topic
Probability and statistics, A-Level Mathematics (syllabus 9709). Structured question, 10 marks.
Source
A-Level Mathematics, May/June 2022 Paper 5 Variant 2, question 6.

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