Two particles P and Q, of masses 0.3kg and 0.2kg respectively, are attached to the ends of a light inextensible string. The string passes over a fixed smooth pulley at B which is attached to two inclined planes. P lies on a smooth plane AB which is inclined at 60° to the horizontal. Q lies on a plane BC which is inclined at 30° to the horizontal. The string is taut and the particles can move on lines of greatest slope of the two planes (see diagram). [Figure 6.1]
- (a)It is given that the plane BC is smooth and that the particles are released from rest. Find the tension in the string and the magnitude of the acceleration of the particles.[5]
- (b)It is given instead that the plane BC is rough. A force of magnitude 3N is applied to Q directly up the plane along a line of greatest slope of the plane. Find the least value of the coefficient of friction between Q and the plane BC for which the particles remain at rest.[5]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [M1] Attempt to use Newton's Second law
- [A1] For any one equation [e.g. For P: 0.3g sin 60 - T = 0.3a]
- [A1] For any second equation [e.g. For Q: T + 0.2g sin 30 = 0.2a]
- [M1] For solving for a or T
- [A1] Magnitude of acceleration = 7.20 ms⁻² Tension = 0.439 N
- [B1] R = 0.2g cos 30
- [B1] Equilibrium for P [0.3g sin 60 - T = 0 or T = 3√3 / 2 or T = 2.598...]
- [M1] Equilibrium for Q on the point of moving down [T + 0.2g sin 30 - F - 3 = 0]
- [M1] Use of F = µR
- [A1] µ = 0.345
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