A-LevelMathematicsTrigonometry9709/21 · May/June 2022 · Q26 Marks
Express the equation 7 tan θ + 4 cot θ – 13 sec θ = 0 in terms of sin θ only.
- (a)Express the equation 7 tan θ + 4 cot θ – 13 sec θ = 0 in terms of sin θ only.[3]
- (b)Hence solve the equation 7 tan θ + 4 cot θ – 13 sec θ = 0 for 0° < θ < 360°.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [1] Attempt to express left hand side of the equation in terms of sin θ and cos θ with at least two of the terms correct and no missing θs Condone use of x instead of θ
- [1] Obtain 7 sin² θ + 4cos² θ – 13sin θ [=0] SOI, OE
- [1] Obtain 3sin² θ – 13sin θ + 4 = 0 Allow if missing θs are recovered
- [1] Attempt solution of 3-term quadratic equation for sin θ
- [1] Obtain sin θ = 1/3 and hence 19.5 or greater accuracy
- [1] Obtain second value 160.5 or greater accuracy; and no other values within the given range FT on 180° - their 19.5°
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