In the past, the time, in hours, for a particular train journey has had mean 1.40 and standard deviation 0.12. Following the introduction of some new signals, it is required to test whether the mean journey time has decreased.
- (a)State what is meant by a Type II error in this context.[1]
- (b)The mean time for a random sample of 50 journeys is found to be 1.36 hours. Assuming that the standard deviation of journey times is still 0.12 hours, test at the 2.5% significance level whether the population mean journey time has decreased.[5]
- (c)State, with a reason, which of the errors, Type I or Type II, might have been made in the test in part (b).[2]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- [B1] Conclude (mean) (journey) time has not decreased when in fact it has. OE in context
- [B1] Ho: Pop mean (or μ) = 1.4 H1: Pop mean (or μ) < 1.4 May be seen in (a)
- [M1] (1.36-1.4) / (0.12/√50) Accept totals method (68-70)/(0.12/√50 × 50) No mixed methods or no standard deviation/variance mixes
- [A1] -2.357 or -2.36 Correct z or correct area if used
- [M1] -2.357 < -1.96 or 0.0092 < 0.025 or 0.9908 > 0.975 Or CV method 1.36 < 1.367 valid comparison
- [A1 FT] There is evidence that (mean) (journey) times have decreased in context not definite no contradictions NB use of two tail test scores max B0M1A1M1A0 no ft for two tail test
- [*B1 FT] Ho was rejected OE FT Ho was accepted OE
- [DB1 FT] Type I FT Type II
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