The random variable X takes values in the range 1 ≤ x ≤ p, where p is a constant. The graph of the probability density function of X is shown in the diagram. [Figure X.X]
- (a)Show that p = 2.[2]
- (b)Find E(X).[5]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- [M1] (a) 1/2 p(p – 1) = 1; For area =1; For verification methods accept 1/2 × 2 × 1 = 1 or 1/2 × 2 × (p-1) = 1 or = 1/2 × 1 × p = 1 as indication that area=1
- [A1] (a) p = 2; AG - Convincing method and answer. Must see quadratic rearranged to =0 and no errors seen. N.B. Accept convincing verification methods (e.g. statement such as 'assume p = 2' or ‘if p = 2' or 'using p = 2' or showing by clear substitution that p = 2 fits 1/2 p(p – 1) = 1 with clear conclusion)
- [M1] (b) Gradient = 2; equation of line is y = 2x + c; line passes through (1, 0), hence c = −2; y = 2x - 2; May be seen in (a); M1 can be implied by correct answer
- [M1] (b) ∫[1,2] x f(x)dx; For attempting ∫x f(x)dx. Ignore limits, FT their equation.
- [A1 FT] (b) 2 ∫[1,2] (x² - x)dx; 2 [x^3/3 - x^2/2]^2_1; Correct integration FT their f(x)and correct limits
- [A1] (b) 5/3 or 1.67 (3 sf)
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