Find the total number of different arrangements of the 8 letters in the word TOMORROW.
- (a)Find the total number of different arrangements of the 8 letters in the word TOMORROW.[2]
- (b)Find the total number of different arrangements of the 8 letters in the word TOMORROW that have an R at the beginning and an R at the end, and in which the three Os are not all together.[3]
- (c)Four letters are selected at random from the 8 letters of the word TOMORROW. Find the probability that the selection contains at least one O and at least one R.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- M1 8! / (k! m!), k=1 or 2, m=1 or 3, not k=m=1 no additional terms
- A1
- M1 6! / k! – m, 1 ≤ k ≤ 3, m an integer, condone 2×(6!/k!)–m.
- M1 w – 4! or w – 24, w an integer Condone w – 2 × 4!
- A1
- M1 ⁴C₃ × 3! + r or 4× 3! + r or ⁴P₃ × 3! + r, r an integer. Condone 2 × ⁴C₃ × 3! + r. 2 × 4× 3! + r or 2 × ⁴P₃ × 3! + r.
- M1 q + ⁴C₂ × 3! × k or q + ⁴P₂ × 3! × k, k = 1,2, q an integer
- A1
- B1 Outcomes for 2 identifiable scenarios correct, accept unsimplified.
- M1 Add 4 or 5 identified correct scenarios only values, no additional incorrect scenarios, no repeated scenarios, accept unsimplified, condone use of permutations.
- A1 All correct and added
- M1 their '50' / ⁸C₄ , accept numerator unevaluated.
- A1
- B1 Outcomes for 5 identifiable scenarios correct, accept unsimplified.
- M1 Add 9, 10 or 11 identified correct scenarios only values, no additional incorrect scenarios, no repeated scenarios, accept unsimplified, condone use of permutations.
- A1 All correct and added
- M1 their '50' / ⁸C₄, accept numerator unevaluated.
- A1
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