The cubic equation x³ + bx² + cx + d = 0, where b, c and d are constants, has roots α, β, γ. It is given that αβγ =-1.
- (a)State the value of d.[1]
- (b)Find a cubic equation, with coefficients in terms of b and c, whose roots are α+1, β+1, γ+1.[3]
- (c)Given also that γ+1 =-α-1, deduce that (c-2b+3)(b-3) = b-c.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B1] d=1
- [B1] y=x+1⇒ x = y −1
- [M1 A1] Substitutes and expands. y³ + (b−3)y² + (c - 2b + 3)y + b − c = 0
- [B1] β+1=-(b-3)
- [B1] −(α+1)(α+1) = c − 2b + 3
- [M1] Applies product of roots. −(α+1)(β+1)(α+1)= -(b−c)
- [A1] AG ⇒(c-2b+3)(b-3)=b-c
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