Let SN = sum from r=1 to N of (5r + 1)(5r + 6) and TN = sum from r=1 to N of 1/((5r + 1)(5r + 6))
- (i)Use standard results from the List of Formulae (MF10) to show that SN = N(25N² + 90N + 83).[3]
- (ii)Use the method of differences to express TN in terms of N.[4]
- (iii)Find lim (N-3SNTN) as N->∞.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [M1] Expands.
- [M1] Substitutes formulae for Σr and Σr².
- [A1] Simplifies to the given answer (AG).
- [M1 A1] Finds partial fractions.
- [M1] Expresses terms as differences.
- [A1] At least 3 terms including last.
- [M1 A1] Divides S_N by N^3 and takes limits as N→∞
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