The linear transformation T : R⁴ → R⁴ is represented by the matrix M, where M = 3 2 0 1 6 5 -1 3 9 8 -2 5 -3 -2 0 -1
- (i)Find the rank of M.[3]
- (ii)Let K be the null space of T. Find a basis for K.[3]
- (iii)Find the general solution of Mx = (2 5 8 -2) [3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [M1] Attempt to row reduction.
- [A1] Two correct rows only
- [A1] Obtains rank.
- [M1] Solves homogeneous system of equations.
- [M1] Using 2 parameters
- [A1] AEF
- [B1] Finds a particular solution.
- [M1] Using correct format
- [A1FT]
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →