Let t be a positive constant. The line l₁ passes through the point with position vector ti+j and is parallel to the vector -2i-j. The line l₂ passes through the point with position vector j+tk and is parallel to the vector -2j+k. It is given that the shortest distance between the lines l₁ and l₂ is √21.
- (a)Find the value of t.[5]
- (b)The plane Π₁ contains l₁ and is parallel to l₂. Write down an equation of Π₁, giving your answer in the form r = a+λb+μc.[1]
- (c)The plane Π₂ has Cartesian equation 5x-6y+7z = 0. Find the acute angle between l₂ and Π₂.[3]
- (d)Find the acute angle between Π₁ and Π₂.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- [B1] Finds vector from any point on l₁ to any point on l₂.
- [M1 A1] Finds common perpendicular.
- [M1 A1] Uses formula for shortest distance.
- [B1 FT] Using their value of t.
- [M1 A1] Uses dot product of -2j+k and normal.
- [A1]
- [M1 A1 FT] Dot product using their normal to Π₁.
- [A1]
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →