The truth table for a logic circuit is shown. INPUT OUTPUT A B C D T 0 0 0 0 0 0 0 0 1 1 0 0 1 0 0 0 0 1 1 1 0 1 0 0 0 0 1 0 1 0 0 1 1 0 0 0 1 1 1 0 1 0 0 0 0 1 0 0 1 1 1 0 1 0 0 1 0 1 1 1 1 1 0 0 0 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1
- (a)Write the Boolean logic expression that corresponds to the given truth table as the sum-of-products. T =[3]
- (b)Complete the Karnaugh map (K-map) for the given truth table. AB CD 00 01 11 10 00 01 11 10[2]
- (c)Draw loop(s) around appropriate group(s) in the K-map to produce an optimal sum-of-products.[2]
- (d)(i)Write the Boolean logic expression from your answer to part (c) as the simplified sum-of-products. T =[2]
- (d)(ii)Use Boolean algebra to write your answer to part (d)(i) in its simplest form. T =[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [3] (T =) Ā. B. C. D + Ā. B. C. D + A. B. C. D + A. B. C. D + A. B. C. D + A. B. C. D (Award 1 mark for every two correct products shown, up to Max 3)
- [2] All K-map cells correctly filled as shown in the mark scheme diagram.
- [1] Loop around cells (AB=11,CD=01), (AB=11,CD=11), (AB=10,CD=01), (AB=10,CD=11) (simplifying to A.D)
- [1] Loop around cells (AB=00,CD=01), (AB=00,CD=11) (simplifying to Ā.B̄.D)
- [1] Any correct Boolean term (e.g., A.D or Ā.B̄.D)
- [1] Boolean terms and operator correct and no other terms present (T = A. D + B. D // B. D. + A. D)
- [1] D. (A. B)
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