A logic expression is given: S = (A AND B AND C) OR (B XOR C)
- (a)Draw the logic circuit for the given expression.[4]
- (b)Complete the truth table for the logic expression: S = (A AND B AND C) OR (B XOR C) A B C | Working space | S 0 0 0 | | 0 0 1 | | 0 1 0 | | 0 1 1 | | 1 0 0 | | 1 0 1 | | 1 1 0 | | 1 1 1 | | [2]
Mark scheme
Marking points from the official mark scheme (May/June 2021). The mark or mark type is shown in brackets.
- [1] (a) Correct 3-input AND gate (or chained 2-input AND gates for A AND B AND C)
- [1] (a) Correct XOR gate for B XOR C
- [1] (a) Correct OR gate combining outputs of AND and XOR gates
- [1] (a) Correct inputs to all gates
- [1] (b) Correct values for S for the first 4 rows (0, 1, 1, 0)
- [1] (b) Correct values for S for the last 4 rows (0, 1, 1, 1)
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