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A-LevelComputer ScienceHardware9618/31 · May/June 2025 · Q58 Marks

This truth table represents a logic circuit. INPUT OUTPUT A B C D Z 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 0 1 1 0 0 1 0 0 0 0 1 0 1 1 0 1 1 0 0 0 1 1 1 1 1 0 0 0 1 1 0 0 1 0 1 0 1 0 0 1 0 1 1 0 1 1 0 0 0 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1

  1. (a)Write the Boolean logic expression that corresponds to the given truth table as the sum-of-products. Z =[2]
  2. (b)(i)Complete the Karnaugh map (K-map) for the given truth table. AB CD 00 01 11 10 00 01 11 10[2]
  3. (b)(ii)Draw loop(s) around appropriate group(s) in the K-map to produce an optimal sum-of-products.[2]
  4. (b)(iii)Write the Boolean logic expression from your answer to part (b)(ii) as the simplified sum-of-products. Z =[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.

  1. [2] All six correct terms: Z = A.B.C.D + Ā.B.C̄.D + Ā.B.C.D + A.B̄.C̄.D̄ + A.B.C̄.D + A.B.C.D
  2. [2] Correct K-map completion
  3. [1] Loop covering cells (AB=01, CD=01), (AB=01, CD=11), (AB=11, CD=01), (AB=11, CD=11)
  4. [1] Loop covering cells (AB=00, CD=00) and (AB=10, CD=00) (wrap-around)
  5. [1] One correct Boolean term (e.g. B.D)
  6. [1] Boolean terms and operator correct and no other terms present: z = B.D + B̄C̄D̄

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About this question

Topic
Hardware, A-Level Computer Science (syllabus 9618). Structured question, 8 marks.
Source
A-Level Computer Science, May/June 2025 Paper 3 Variant 1, question 5.

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