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A-LevelChemistryElectrochemistry9701/42 · Feb/Mar 2017 · Q38 Marks

(a) The diagram shows the apparatus used to measure the standard electrode potential, E°, of Fe³⁺(aq)/Fe²⁺(aq). [Figure showing apparatus for standard electrode potential measurement, with labels A-F]

  1. (a)(i)Identify what the letters A to F represent. A B C D E F[3]
  2. (a)(ii)Label the diagram to show • which is the positive electrode, • the direction of electron flow in the external circuit. Use the Data Booklet to help you.[1]
  3. (b)In another experiment, an Fe³⁺(aq)/Fe²⁺(aq) half-cell was connected to a Cu²⁺(aq)/Cu(s) half-cell. Determine the standard cell potential, E°cell, when these two half-cells are connected by a wire and the circuit is completed. Use the Data Booklet to help you. E°cell = V [1][1]
  4. (c)(i)The E° of Ni²⁺(aq)/Ni(s) is −0.25V. State and explain how the electrode potential changes if the concentration of Ni²⁺(aq) is decreased.[1]
  5. (c)(ii)The E° of Cr³⁺(aq)/Cr²⁺(aq) is -0.41 V. Calculate the electrode potential when [Cr³⁺(aq)] is 0.60 mol dm⁻³ and [Cr²⁺(aq)] is 0.15 mol dm⁻³. Use the Nernst equation. E = E° + 0.059/z log [oxidised species]/[reduced species] E = V [2][2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.

  1. [3] A - H2, 1 atm; B - platinum; C - 1 mol dm⁻³ H⁺ / HCl etc.; D - salt bridge / KNO3 etc.; E - platinum; F - 1 mol dm⁻³ Fe²⁺ AND 1 mol dm⁻³ Fe³⁺
  2. [1] positive electrode is (Pt) on RHS AND electrons flow clockwise
  3. [1] cell potential is 0.77 – 0.34 =(+) 0.43 (V)
  4. [1] electrode potential would become more negative as equilibrium shifts to left / explanation in terms of the Nernst equation
  5. [1] E = −0.41 + (0.059/1)log(0.60/0.15) = -0.41 + 0.059 log 4.0
  6. [1] E = -0.37 (V)

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About this question

Topic
Electrochemistry, A-Level Chemistry (syllabus 9701). Structured question, 8 marks.
Source
A-Level Chemistry, Feb/Mar 2017 Paper 4 Variant 2, question 3.

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