The amino acid tyrosine can be synthesised from phenol by the route shown. OH step 1 CHO step 2 CN HO HO phenol HO step 3 NH2 Cl OH step 5 step 4 CO₂H CO₂H HO HO 1. PCl5 2. H₂O CO₂H HO tyrosine
- (a)(i)Name the mechanism occurring in the following steps. step 1 step 2[2]
- (a)(ii)What type of reaction is occurring in step 3?[1]
- (a)(iii)Suggest reagents and conditions for each of the following steps. step 1 step 2 step 3 step 5[5]
- (a)(iv)Draw the structures of the products of the reactions of tyrosine with an excess of each of the following reagents. with NaOH(aq) with HCl(aq) with Br2(aq)[4]
- (b)(i)Which species is responsible for spot P? Explain your answer.[2]
- (b)(ii)Suggest why the other two species give spots R and S that are so close together.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [1] step 1 electrophilic substitution ignore acylation
- [1] step 2 nucleophilic addition
- [1] hydrolysis
- [1] step 1 CICH2CHO (allow Br, I for Cl)
- [1] AlCl3
- [1] step 2 HCN + NaCN
- [1] step 3 heat in H3O⁺ / heat H⁺(aq)
- [1] step 5 NH3 under pressure (+ heat) or heat NH3 in a sealed tube
- [1+1] Structure of tyrosine with NaOH(aq) product (deprotonated -OH and -CO2H).
- [1] Structure of tyrosine with HCl(aq) product (protonated -NH2).
- [1] Structure of tyrosine with Br2(aq) product (bromination of phenol ring, one Br on each ortho position relative to -OH, and Br in meta position if meta to -OH is unsubstituted, or 2 Br if no meta position occupied by another group). The MS shows 2 Br atoms ortho to -OH.
- [1] P is tyr
- [1] tyr is 2- AND it is small / has a small Mr
- [1] (dipeptide / phe-tyr) 2– is about double the Mr / mass of (phe) 1
- [1] OR mass / charge ratios are about the same for each (for dipeptide / phe-tyr and phe)
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