The table lists some organic acids and their pKa values. acid formula pKa ethanoic acid CH3CO₂H 4.76 chloroethanoic acid CICH₂CO₂H 2.86 aminoethanoic acid (glycine) H2NCH2CO2H 9.87
- (a)(i)State the relationship between pKa and the strength of an acid.[1]
- (a)(ii)State the mathematical relationship between pKa and the acidity constant Ka.[1]
- (a)(iii)Give reasons for why the pKa value for chloroethanoic acid is smaller than that for ethanoic acid.[2]
- (b)(i)Use the zwitterionic structure for aminoethanoic acid (glycine) in aqueous solution to write an equation for its dissociation giving H+(aq) ions.[1]
- (b)(ii)Calculate the pH of a 0.100 moldm-³ solution of aminoethanoic acid. pH = ...[2]
- (b)(iii)A 10.0 cm³ sample of 0.100 mol dm-3 aminoethanoic acid (glycine) was titrated with 0.100 mol dm-3 NaOH. After 20.0 cm³ of NaOH, an excess, had been added, the pH was found to be 12.5. Using the following axes, sketch a graph showing how the pH changes during this titration.[3]
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Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [1] the lower / smaller the pKa, the stronger the acid
- [1] pKa = -log(Ka) or pKa = -lg(Ka) or Ka = 10⁻pKa
- [1] (stronger than ethanoic acid because) Cl is electron-withdrawing
- [1] and so stabilises the RCO2⁻ anion / conjugate base or weakens O-H bond (so H⁺ is more easily released)
- [1] NH3⁺CH2CO2⁻ → NH2CH2CO2⁻ + H⁺ OR NH3⁺CH2CO2⁻ + H2O → NH2CH2CO2⁻ + H3O⁺
- [1] Ka = 10⁻9.87 = 1.35 × 10⁻¹⁰
- [1] [H⁺] = √(Ka.c) = 3.67 × 10⁻⁶ pH = 5.4 (5.43–5.44) min 2sf
- [1] curve starts at 5.4 and continuous
- [1] vertical portion (end point) at vol added = 10.0 cm³
- [1] finishes at pH = 12.5 at 20 cm³ (and does not increase in pH)
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