You are to determine the enthalpy change of neutralisation for a different acid from that used in Question 1. The acid is represented by HB where B⁻ represents the anion. HB(aq) + NaOH(aq) → NaB(aq) + H₂O(l) FB 3 is 2.00 mol dm⁻³ acid, HB. FB 4 is 72.00 g dm⁻³ sodium hydroxide, NaOH.
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