Combustion data can be used to calculate the empirical formula, molecular formula and relative molecular mass of many organic compounds.
- (a)Define the term relative molecular mass.[2]
- (b)(i)T is an alcohol, CₓHᵧO. A gaseous sample of T occupied a volume of 20 cm³ at 120°C and 100 kPa. The sample was completely burned in 200 cm³ of oxygen (an excess). The final volume, measured under the same conditions as the gaseous sample, was 250 cm³. Under these conditions, all water present is vaporised. Removal of the water vapour from the gaseous mixture decreased the volume to 170 cm³. Treating the remaining gaseous mixture with concentrated alkali, to absorb carbon dioxide, decreased the volume to 110 cm³. The equation for the complete combustion of T can be represented as shown. CₓHᵧO + zO₂ → xCO₂ + (y/2)H₂O Use the data given to calculate the value of x.[1]
- (b)(ii)Use the data given to calculate the value of y.[1]
- (b)(iii)If you were unable to calculate values for x and y then use x = 4 and y = 10 for the remaining parts of this question. These are not the correct values. Complete the equation for the complete combustion of the alcohol, T. ................. + .........O₂ → ................CO₂ + ................H₂O[1]
- (b)(iv)Give the skeletal formulae for two possible structures of T. Name each alcohol.[2]
- (b)(v)Use the general gas equation to calculate the mass of T present in the original 20 cm³ gaseous sample, which was measured at 120°C and 100kPa. Give your answer to three significant figures. Show your working.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [1] The mass of a molecule
- OR the (weighted) average / (weighted) mean mass of the molecules
- [1] Relative / compared to 1/12 (the mass) of an atom of carbon-12
- OR on a scale in which a carbon-12 atom / isotope has a mass of (exactly) 12 (units)
- [1] 3
- [1] 8
- [1] C₃H₈O + 4½O₂ → 3CO₂ + 4H₂O
- [1] OH AND propan-2-ol / 2-propanol (skeletal formula shown in mark scheme)
- [1] OH AND propan-1-ol / 1-propanol (skeletal formula shown in mark scheme)
- Alternative answers (any two):
- OH AND butan-1-ol / 1-butanol (skeletal formula shown in mark scheme)
- OH AND butan-2-ol / 2-butanol (skeletal formula shown in mark scheme)
- OH AND (2-)methylpropan-1-ol / (2–)methyl-1-propanol (skeletal formula shown in mark scheme)
- OH AND (2-)methylpropan-2-ol / (2–)methyl-2-propanol (skeletal formula shown in mark scheme)
- [1] correct conversions of data to SI/consistent units p = 100 000 ; V = 20 × 10⁻⁶ ; T = 393
- [1] calculation of n ( = pV/RT) from M1 values n = 100×10³×20×10⁻⁶ / 8.31×393
- [1] calculation of mass m ( = n × Mr) AND answer correct to 3sf m = 6.12 × 10⁻⁴ × 60 = 0.0367 (g)
- Alternative answer for using C₄H₁₀O: m = 6.12 × 10⁻⁴ × 74 = 0.0453 (g)
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