The equation for the complete combustion of propan-1-ol is shown. CH₃CH₂CH₂OH(l) + 4½ O₂(g) → 3CO₂(g) + 4H₂O(l) Standard enthalpy changes of formation are given. compound ΔH CH₃CH₂CH₂OH(l) -303 kJ mol⁻¹ CO₂(g) -394 kJ mol⁻¹ H₂O(l) -286 kJ mol⁻¹ What is the standard enthalpy change of combustion of propan-1-ol, in kJ mol⁻¹?
✓ Correct answer
B: 303 – (4 × 286) – (3 × 394)
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