Compound Q can be synthesised from chlorobenzene in seven steps, using the route shown in Fig. 5.1. [Figure 5.1, showing a seven-step reaction scheme starting from chlorobenzene to compound Q]
- (a)(i)Write an equation for the formation of the electrophile for step 1.[1]
- (a)(ii)Complete the mechanism in Fig. 5.2 for step 1, the alkylation of chlorobenzene. Include all relevant curly arrows and charges. Draw the structure of the intermediate. [Figure 5.2, partial mechanism starting from chlorobenzene, showing intermediate box and final product with H+][3]
- (a)(iii)Step 2 is an oxidation reaction. Construct an equation for the reaction in step 2. Use [O] to represent an atom of oxygen from an oxidising agent.[1]
- (a)(iv)Suggest reagents for the conversion of K to M in steps 3 and 4. step 3 step 4[2]
- (a)(v)Identify the type of reaction that occurs in step 5.[1]
- (a)(vi)Step 7 takes place when P is heated with a weak base such as K2CO3(aq). [Figure showing reaction of P with HN to form Q] Suggest why a strong base such as NaOH(aq) is not used for this reaction.[1]
- (a)(vii)Q is optically active. Explain the meaning of optically active.[1]
- (a)(viii)Give two reasons why it might be desirable to synthesise a single optical isomer of Q for use as a drug. 1 2[2]
- (b)Q is commonly used in conjunction with aspirin. aspirin [Figure showing structure of aspirin] Aspirin is a weak Brønsted-Lowry acid.
- (b)(i)The pKa of aspirin is 3.49. 75mg of aspirin dissolves in water to form 100cm³ of an aqueous solution. Calculate the pH of this solution. [Mr: aspirin, 180.0] pH =[3]
- (b)(ii)Aspirin undergoes acid hydrolysis in the stomach. Give the structures of the organic products of this acid hydrolysis.[2]
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Mark scheme
Marking points from the official mark scheme (Feb/Mar 2024). The mark or mark type is shown in brackets.
- [1] AlCl3 + CH3Cl → AlCl4- + CH3+
- [1] curly arrow from inside hexagon to electrophile (CH3+)
- [1] intermediate
- [1] curly arrow from C—H bond into the hexagon AND H+ formed
- [1] C6H4(Cl)CH3 + 2[O] → C6H4(Cl)CHO + H2O
- [1] step 3 HCN AND KCN (cat) OR KCN AND H2SO4/HCl
- [1] step 4 H2SO4(aq) OR HCl (aq)
- [1] addition-elimination / condensation
- [1] (a strong base) it would hydrolyse the ester
- [1] (a substance able to) rotate the plane of plane-polarised light
- [2] any two of: • reduced / different biological activity of ‘other' enantiomer ORA • avoids need to separate the optical isomers to form the pure active isomer • lower dosage required OR (drug is) more potent • higher yield (of biologically-active molecule) • no / less (harmful) side effects OR other isomer can have side effects
- [1] M1 [HA] = (75 × 10-3 / 180) ÷ 0.100 = 4.17 × 10–3 OR 1 / 240 (mol dm³)
- [1] M2 [H+] = (Ka × [HA])½= (10-3.49 × 4.17 × 10−3)½ = 1.16 × 10-3 (mol dm-3)
- [1] M3 pH = -log [H+] = 2.93 to 2.94 min 2sf
- [1] OH-C6H4-COOH (salicylic acid)
- [1] CH3COOH (ethanoic acid)
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