Ruthenium and osmium are transition metals below iron in Group 8 of the Periodic Table.
- (a)Two different complex ions, X and Y, can form when anhydrous RuCl3 reacts with water under certain conditions. X and Y have octahedral geometry. Aqueous samples of X and Y react separately with an excess of AgNO3(aq). Different amounts of AgCl are precipitated: • 1 mole of complex ion X produces 2 moles of AgCl • 1 mole of complex ion Y produces 1 mole of AgCl. (i) Complete Table 4.1 to suggest formulae for X and Y. Table 4.1 | | X | Y | |:-------|:--|:--| | formula of complex | | | [2]
- (a)(ii)Both complexes react with an excess of bipyridine, bipy, to form a mixture of two stereoisomers of [Ru(bipy)3]3+. bipy [Figure 4.1, structure of bipyridine shown with N-N bonds] Bipyridine is a bidentate ligand. Draw three-dimensional diagrams of the two stereoisomers of [Ru(bipy)3]3+. Use N N to represent the bipy ligand in your structures. [2]
- (b)Fig. 4.1 shows another ruthenium complex. [Figure 4.1, structure of (H3N)5Ru-N(pyrazine)N-Ru(NH3)5]5+ This complex contains the neutral ligand pyrazine. pyrazine [Figure, structure of pyrazine with N=N atoms]
- (b)(i)Suggest how pyrazine is able to bond to two separate ruthenium ions.[1]
- (b)(ii)Pyrazine is an aromatic compound. The bonding and structure of pyrazine is similar to that of benzene. Describe and explain the shape of pyrazine. In your answer, include: • the hybridisation of the nitrogen and carbon atoms • how orbital overlap forms π bonds between the atoms in the ring.[2]
- (b)(iii)Predict the number of peaks seen in the carbon-13 NMR spectrum of pyrazine. Explain your answer.[2]
- (b)(iv)The overall charge of the ruthenium complex in Fig. 4.1 is 5+. Deduce the possible oxidation states of the two ruthenium ions in the complex.[1]
- (c)Osmium tetroxide, OsO4, reacts with alkenes in a similar manner to cold dilute acidified MnO4-. Fig. 4.2 shows a proposed synthesis of a condensation polymer G. [Figure 4.2, reaction scheme for polymer G synthesis]
- (c)(i)Suggest a reagent for step 1.[1]
- (c)(ii)Draw the structure of exactly one repeat unit of the condensation polymer G. The ester linkage should be shown fully displayed.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2024). The mark or mark type is shown in brackets.
- [1] X [Ru(H2O)5Cl]2+
- [1] Y [Ru(H2O)4Cl2]+ ECF [1] if reversed
- [2] N N Ru N N Ru N N
- [1] (pyrazine has) a lone pair on each N (atoms) / two lone pairs (on the N's) AND which can be donated / form a coordinate / dative bond (with Ru)
- [1] • shape is (hexagonal ring) planar / (trigonal) planar / 120°
- [1] • carbons and nitrogens are sp² hybridised
- [1] • a p orbital (from each atom) overlaps sideways/laterally (with each other above and below the ring forming π bonds) mark as ✓✓
- [1] 1/one
- [1] all the carbon atoms are equivalent / in same environment OR pyrazine is a symmetrical molecule u/c
- [1] +2/2+ AND +3/3+ OR +4/4+ AND +1/1+
- [1] SOCl2 OR PCl3 OR PCl5
- [1] M1 correct ester linkage in the middle of the polymer (displayed C=O bond attached to benzene ring)
- [1] M2 rest of structure
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