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A-LevelChemistryIntroduction to organic chemistry9701/42 · Feb/Mar 2023 · Q427 Marks

Ethylamine and phenylamine are primary amines. ethylamine CH3CH2NH2 phenylamine NH2 [Figure 4.1]

  1. (a)(i)Ethylamine forms when ethanamide, CH3CONH2, is reduced by LiAlH4. Write an equation for this reaction. Use [H] to represent one atom of hydrogen from the reducing agent.[1]
  2. (a)(ii)Ethylamine is a product of the reaction of bromoethane with ammonia. Name the mechanism of this reaction and state the conditions used. mechanism .............................................. conditions ..............................................[2]
  3. (a)(iii)The reaction in (a)(ii) also forms secondary and tertiary amines. Suggest the identity of a secondary or tertiary amine formed by the reaction in (a)(ii).[1]
  4. (b)Ethylamine is a weak base. State the relative basicities of ammonia, ethylamine and phenylamine. Explain your answer. least basic < .............................................. < .............................................. most basic[4]
  5. (c)Pure phenylamine, C6H5NH2, can be prepared from benzene in two steps. Draw the structure of the intermediate compound. Suggest reagents and conditions for each step.[3]
  6. (d)(i)Draw the structure of W, the organic product of reaction 1.[1]
  7. (d)(ii)State the reagents used in reaction 2.[1]
  8. (d)(iii)Benzenediazonium chloride, C6H5N2Cl, and X react together in reaction 4 to form Y, an azo compound. Name X, the organic product of reaction 3.[1]
  9. (d)(iv)State the necessary conditions for reaction 4 to occur.[1]
  10. (d)(v)Suggest a use for Y.[1]
  11. (e)(i)Define monodentate ligand.[2]
  12. (e)(ii)Cu²⁺(aq) reacts with CH3NH2 to form [Cu(CH3NH2)2(H2O)4]²⁺. Draw three-dimensional diagrams to show the two geometrical isomers of [Cu(CH3NH2)2(H2O)4]²⁺.[2]
  13. (e)(iii)State the coordination number of copper in [Cu(CH3NH2)2(H2O)4]²⁺.[1]
  14. (f)(i)Give the units of Kstab for equilibrium 1.[1]
  15. (f)(ii)Write an expression for Kstab for equilibrium 3.[1]
  16. (f)(iii)A solution of Cl⁻(aq) is added to Cd²⁺(aq) and allowed to reach equilibrium. The equilibrium concentrations are given. [Cd²⁺(aq)] = 0.043 mol dm⁻³ [Cl⁻(aq)] = 0.072 mol dm⁻³ Use your expression in (f)(ii) to calculate the concentration of CdCl4²⁻(aq) in the equilibrium mixture. [CdCl4²⁻(aq)] = .............................................. mol dm⁻³[1]
  17. (f)(iv)When CH3NH2(aq) is added to Cd²⁺(aq), a mixture of [Cd(CH3NH2)4]²⁺(aq) and [Cd(OH)4]²⁻(aq) forms. Suggest how the [Cd(OH)4]²⁻(aq) is formed.[1]
  18. (f)(v)Cd²⁺(aq) exists as a complex ion, [Cd(H2O)6]²⁺(aq). Identify the most stable and the least stable of the complexes in Table 4.1 by placing one tick (✔) in each column. Explain your answer. complex [Cd(H2O)6]²⁺(aq) [Cd(OH)4]²⁻(aq) [Cd(CH3NH2)4]²⁺(aq) [CdCl4]²⁻(aq) explanation[2]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2023). The mark or mark type is shown in brackets.

  1. [1] CH3CONH2 + 4[H] → CH3CH2NH2 + H2O
  2. [1] nucleophilic substitution
  3. [1] (ammonia with) ethanol AND heat under pressure OR ethanol AND heat in a sealed tube
  4. [1] (CH3CH2)2NH OR (CH3CH2)3N
  5. [1] (least) phenylamine < ammonia < ethylamine (most)
  6. [1] explanation: (order of basicity) ability of base AND to accept a proton OR donate its lone pair (to a proton)
  7. [1] phenylamine • lone pair/p-orbital from N delocalised / overlaps with (π-)ring / benzene
  8. [1] ethylamine • alkyl/ethyl group is electron donating group / +I group • increases electron density on N (ethylamine) ORA any two [1] any three [2] all four [3]
  9. [1] NO2 [structure of nitrobenzene]
  10. [1] concentrated HNO3 and H2SO4 (and 25–60 °C)
  11. [1] (reduction with) Sn and concentrated HCl (heat)
  12. [1] NH2 Br. Br Br [structure of 2,4,6-tribromophenylamine]
  13. [1] nitrous acid / HNO2 OR NaNO2 AND dilute HCl
  14. [1] phenol
  15. [1] NaOH/alkali
  16. [1] dyestuffs / dyes
  17. [1] species that uses one lone pair of electrons
  18. [1] that forms a single dative covalent bond to a central metal atom/ion
  19. [1] correct 3D cis isomer
  20. [1] correct 3D trans isomer
  21. [1] 6
  22. [1] units = mol⁻⁴ dm¹²
  23. [1] (Kstab =) [CdCl4²⁻] / ([Cd²⁺][Cl⁻]⁴)
  24. [1] [CdCl4²⁻] = Kstab × 0.043 × 0.072⁴ = 7.28/7.3 × 10⁻⁴ (mol dm⁻³) min 2sf
  25. [1] CH3NH2 (is basic so) reacts with water to produce OH⁻ that reacts with Cd²⁺ OR CH3NH2 acts as a base and accepts a proton from Cd[H2O)6]2⁺ / water
  26. [1] OR [Cd(H2O)6]2⁺ + 4CH3NH2 → [Cd(OH)4(H2O)2]²⁻ + 4CH3NH3⁺ OWTTE
  27. [1] Cd(OH)4²⁻ = most stable (2nd box) AND [Cd(H2O)6]2⁺ = least stable (first box)
  28. [1] Cd(OH)4²⁻ has highest Kstab (and all Kstab values given > 1)

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About this question

Topic
Introduction to organic chemistry, A-Level Chemistry (syllabus 9701). Structured question, 27 marks.
Source
A-Level Chemistry, Feb/Mar 2023 Paper 4 Variant 2, question 4.

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