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A-LevelChemistryEquilibria9701/42 · Feb/Mar 2022 · Q119 Marks

Iodine is found naturally in compounds in many different oxidation states.

  1. (a)(i)Identify the role of H2O2(aq) in its reaction with I- ions in acidic conditions. Write an ionic equation for the reaction.[2]
  2. (a)(ii)15.0 cm³ of C6H12 is shaken with 20.0cm³ of an aqueous solution containing I₂ until no further change is seen. It is found that 0.390 g of I₂ is extracted into the C6H12. The partition coefficient of I₂ between C6H12 and water, Kpc, is 93.8. Calculate the mass of I2 that remains in the aqueous layer. Show your working.[2]
  3. (a)(iii)Suggest how the value of Kpc of I2 between hexan-2-one, CH3(CH2)3COCH3, and water compares to the value given in (a)(ii). Explain your answer.[2]
  4. (b)(i)Define enthalpy change of solution.[1]
  5. (b)(ii)Use the data in Table 1.1 to calculate the enthalpy change of solution of potassium iodide, KI. Table 1.1 process enthalpy change, ∆H/kJmol⁻¹ K⁺(g) + I⁻(g) → KI(s) −629 K⁺(g) → K⁺(aq) −322 I⁻(g) → I⁻(aq) −293[1]
  6. (b)(iii)Suggest the trend in the magnitude of the lattice energies of the Group 1 iodides, LiI, NaI, KI. Explain your answer.[2]
  7. (c)(i)A 25.0 cm³ portion of a Cu²⁺(aq) solution reacts with an excess of I⁻(aq). The end-point of the titration occurs when 22.30 cm³ of 0.150 moldm⁻³ S2O3²⁻(aq) is added. Calculate the concentration of Cu²⁺(aq) in the original solution.[2]
  8. (c)(ii)Identify a suitable indicator for the titration.[1]
  9. (c)(iii)Copper(I) and copper(II) both contain electrons in all five 3d orbitals. Sketch the shape of a 3dxy orbital on the axes provided. [Figure with Z, y, X axes][1]
  10. (d)The reaction of I⁻ ions with persulfate ions, S₂O₈²⁻, can be catalysed by Fe³⁺ ions. 2I⁻ + S2O8²⁻ → I₂ + 2SO4²⁻ Write equations to show how Fe³⁺ catalyses this reaction.[2]
  11. (e)An orange precipitate of HgI2 forms when Hg²⁺ ions are added to KI(aq). The solubility of HgI2 at 25 °C is 1.00 × 10⁻⁷gdm⁻³. Calculate the solubility product, Ksp, of HgI2. Include units in your answer. [Mr: HgI2, 454.4][3]

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Mark scheme

Marking points from the official mark scheme (Feb/Mar 2022). The mark or mark type is shown in brackets.

  1. [1] oxidising agent
  2. [1] H2O2 + 2H+ + 2I¯ → 2H2O + I2
  3. [2] M1: Kpc (93.8) = [I2(cyclohexane)] + [I2(aq)] ; 93.8 = (0.390/15) ÷ (x/20) ; M2: mass of I2(aq), x = 5.54 × 10-3 (g) ecf
  4. [2] • Kpc would be lower ; • hexan-2-one is more polar (than cyclohexane) OR hexan-2-one is polar AND cyclohexane is non-polar ; • I2 is (therefore) less soluble in hexan-2-one
  5. [1] enthalpy change when one mole of a solute AND dissolves in water to form a solution of infinite dilution
  6. [1] -(-629) + (−322) + (−293) = (+)14 (kJ mol-1)
  7. [2] (cationic) charge density decreases Li+ to K+ [1] ; so lattice energies become less negative / less exothermic AND because less attraction between ions [1]
  8. [2] M1: moles of thiosulfate = 0.02230 × 0.150 = 3.345 × 10-3 ; M2: [Cu2+] = 2 × ½ × 3.345 × 10–3 ÷ 0.0250 = 0.134 (mol dm-³) ecf
  9. [1] starch
  10. [1] [3dxy orbital diagram] ; 3dxy
  11. [1] Reduction of Fe3+: 2Fe3+ + 2I- → 2Fe2+ + I2 ; [1] Regeneration of Fe3+: 2Fe2+ + S2O82− → 2Fe3+ + 2SO42-
  12. [3] M1: ([Hg2+]) = 1.00 × 10–7 ÷ 454.4 = 2.20 × 10-10 (mol dm-3) ; M2: Ksp = [Hg2+][I-]2 = 4[Hg2+]3 = 4.26 × 10-29 ecf ; M3: units = mol³ dm-9 ecf

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About this question

Topic
Equilibria, A-Level Chemistry (syllabus 9701). Structured question, 19 marks.
Source
A-Level Chemistry, Feb/Mar 2022 Paper 4 Variant 2, question 1.

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